Final answer:
The distance traveled by the toy in the next t seconds will be three times the distance covered in the first t seconds, which is 30 meters. The correct answer is (c) 30t.
Step-by-step explanation:
The question is based on the concept of motion with constant acceleration in physics. When a toy starts from rest and travels a distance of 10 meters in t seconds under constant acceleration, the distance covered in the next t seconds can be found using the kinematic equation s = ut + ½ at², where s is the distance, u is the initial velocity, a is the acceleration, and t is the time.
Since the initial velocity u is zero (starting from rest), the distance covered in the first t seconds is given by s = ½ at². For the second interval of t seconds, the initial velocity is no longer zero but is the final velocity at the end of the first interval. Thus by using the kinematic equations considering the velocity at the end of the first interval, we find that the distance covered in the second interval is three times the distance covered in the first interval, or 30 meters.
The correct answer is (c) 30t, which corresponds to three times the original distance (10 meters) traveled during the first interval of t seconds.