Question

In a building there are 15 bulbs of 45w , 15 bulbs of 100w,15 small fans of 10w and 2 heaters of 1kw . the voltage of electric main supply is 220v . the minimum fuse capacity (rated value) of the building will be:

A. 10 A
B. 20 A
C. 25 A
D. 15 A

Answer 1

The correct minimum fuse capacity for the building based on the total power consumption of 4325W and 220V supply is 20 A. The correct option is (B).

Step-by-step explanation:

The question requires the calculation of the minimum fuse capacity for a building based on the total power consumption of various electrical devices operating on a 220V supply.

Step-by-Step Explanation:

1. First, calculate the total power consumption by adding the power of all devices:
2. The total power consumption: 2175W + 150W + 2000W = 4325W
3. Calculate the total current using the formula I = P/V where I is the current, P is the total power, and V is the voltage:
4. 
   
5. I = 4325W / 220V ≈ 19.66A
6. Choose the minimum fuse capacity that is higher than the total current: 20A should suffice, as it is the next standard size available after the calculated current.

Therefore, the correct option for the minimum fuse capacity of the building would be 20 A as per option B.