Question

What is the equilibrium cant on a 2 degree curve on a broad gauge if 15 trains, 10 trains, 5 trains and 2 trains are running at speeds of 50 km. p.h., 60 km.p.h., 70 km. p.h. and 80 km. p.h. respectively?

Answer 1

The equilibrium cant on a curve is the angle at which the track of a railway is inclined to counterbalance the centrifugal force. The formula to find the equilibrium cant is cant = arctan(speed^2 / (g * radius)).

Step-by-step explanation:

The equilibrium cant on a curve is the angle at which the track of a railway is inclined to the horizontal in order to counterbalance the centrifugal force acting on the trains as they navigate the curve. To calculate the equilibrium cant, we need to consider the speed and radius of the curve. The formula to find the equilibrium cant is:

cant = arctan(speed^2 / (g * radius))

where speed is the speed of the train in meters per second, g is the acceleration due to gravity (approximately 9.8 m/s^2), and radius is the radius of the curve in meters.

Let's calculate the equilibrium cant for each train:

• Train 1: Cant = arctan((50 km/h)^2 / (9.8 m/s^2 * 2 degree curve radius))
• Train 2: Cant = arctan((60 km/h)^2 / (9.8 m/s^2 * 2 degree curve radius))
• Train 3: Cant = arctan((70 km/h)^2 / (9.8 m/s^2 * 2 degree curve radius))
• Train 4: Cant = arctan((80 km/h)^2 / (9.8 m/s^2 * 2 degree curve radius))

By plugging in the values, we can calculate the equilibrium cant for each train.