Final answer:
The sequence of events for the transmission of a nerve impulse across a synapse includes the arrival of action potential, fusion of synaptic vesicles, and opening of ion channels to elicit excitatory or inhibitory potentials. The correct options are b,c,a.
Step-by-step explanation:
The transmission of a nerve impulse across a synapse involves a well-defined sequence of events. Beginning with the arrival of the action potential at the axon terminal, which depolarizes the presynaptic membrane and triggers the opening of voltage-gated Na+ channels. The influx of Na+ ions leads to the opening of voltage-gated Ca2+ channels, allowing calcium ions to enter and initiate the fusion of synaptic vesicles with the presynaptic membrane. These vesicles then release neurotransmitters into the synaptic cleft.
Upon reaching the postsynaptic membrane, neurotransmitters bind to receptors, leading to the opening of specific ion channels that generate new excitatory or inhibitory potentials. The correct sequence for the transmission of nerve impulse across a synapse would thus be: (b) arrival of action potential at axon terminal, (c) synaptic vesicle fuses with the synaptic membrane, (a) opening of specific ions channels allows the entry of ions and new excitatory or inhibitory potential are generated.