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An express train is moving with a velocity v₁. its driver finds another train is moving on the same track in the opposite direction with velocity v₂. to escape collision, both trains apply equal deceleration

what is the minimum time needed to avert a collision, considering that both trains must come to rest to do so?

User Vartec
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Final answer:

The minimum time needed to avoid a collision between two trains undergoing the same deceleration and coming to rest is determined by the train with the higher initial velocity; the time to stop is calculated as the initial velocity of that train divided by the deceleration.

Step-by-step explanation:

To calculate the minimum time needed to avert a collision when both trains apply equal deceleration and must come to rest, we use the kinematic equation for uniformly accelerated motion:

v = u + at

Where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

Since both trains must come to rest (v = 0), and if we consider that they apply brakes simultaneously with the same deceleration:

0 = v1 - at

and

0 = v2 - at

The time taken by each train to stop is:

t1 = v1 / a

and

t2 = v2 / a

Since the accelerations are equal for both trains:

t = t1 = t2

The relative velocity between the two trains is vrel = v1 + v2 since they are moving in opposite directions. The total stopping time is determined by the train with the higher velocity, so:

t = max(v1, v2) / a

Therefore, the minimum time to prevent a collision is the highest value of t obtained from the above expression for each train.

User Gmunkhbaatarmn
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