Question

One evening, kaushik was in a park. children were playing . birds were singing on a nearby tree of height 80m. he observed a bird on the tree at an angle of elevation of 45°. when a sixer was hit, a ball flew through the tree frightening the bird to fly away. in 2 seconds, he observed the bird flying at the same height at an angle of elevation of 30° and the ball flying towards him at the same height at an angle of elevation of 60°.

Answer 1

The horizontal position of the mouse when it has fallen 12.0 m is approximately 5.46 meters.

Step-by-step explanation:

To determine the horizontal position of the mouse when it has fallen 12.0 m, we need to consider the vertical motion of the mouse. We can use the formulas of projectile motion to solve this problem. First, we can calculate the time it takes for the mouse to fall 12.0 m using the formula: h = (1/2) * g * t^2. Substituting the given values, we get: 12.0 = (1/2) * 9.8 * t^2, which simplifies to t^2 = 2.449 and t = 1.56 s.

Next, we can find the horizontal distance traveled by the mouse using the formula: d = v * t, where v is the horizontal velocity of the owl. Substituting the given values, we get: d = 3.50 * 1.56 = 5.46 m.

Therefore, the horizontal position of the mouse when it has fallen 12.0 m is approximately 5.46 meters.