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A small telescope has an objective lens of focal length 140cm andan eyepiece of focal length 5.0cm. What is the magnifying power ofthe telescope for viewing distant objects when the telescope is in normal adjustment (i.e., when the final imageis at infinity)?

User Ruwantha
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Final answer:

The magnifying power of a telescope with an objective lens focal length of 140cm and eyepiece focal length of 5.0cm is calculated to be 28 when viewing distant objects with the final image at infinity.

Step-by-step explanation:

The magnifying power of a telescope for viewing distant objects when the telescope is in normal adjustment (final image at infinity) is given by the ratio of the focal lengths of the objective lens to the eyepiece lens. For a small telescope with an objective lens of focal length 140cm and an eyepiece of focal length 5.0cm, the magnifying power (M) can be calculated using the formula:

M = Focal length of the objective lens / Focal length of the eyepiece lens

Plugging in the given values:

M = 140cm / 5.0cm = 28

So, the telescope's magnifying power for viewing distant objects in normal adjustment is 28.

User HanJeaHwan
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