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The work done in pushing a block of mass 10 kg from bottom to the top of a frictionless inclined plane 5 m long and 3 m high is- (g=9.8 m/sec)

(A) 392J
(B) 294J
(C) 98 J
(D) 0.98 J

1 Answer

1 vote

Final answer:

The work done in pushing the block up the inclined plane is 294 J.

Step-by-step explanation:

To calculate the work done in pushing the block up the inclined plane, we need to consider the gravitational potential energy change.

The work done by gravity is given by the formula W = mgh, where m is the mass of the block, g is the acceleration due to gravity, and h is the height of the inclined plane. In this case, m = 10 kg, g = 9.8 m/s², and h = 3 m.

Substituting the values into the formula, we get W = (10 kg)(9.8 m/s²)(3 m) = 294 J.

Therefore, the work done in pushing the block from bottom to top of the inclined plane is 294 J, which corresponds to option (B).

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