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Square key of side d/4 each and length l is used to transmit torque t from the shaft of diameter d to the hub of a pulley. assuming the length of the key to be equal to the thickness of the pulley, the average shear stress developed in the key is given by

A. 4T/ld
B. 16T/ld²
C. 8T/ld²
D. 16T/πd³

User Sulphy
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1 Answer

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Final answer:

The average shear stress in a square key transmitting torque T with side d/4 and length l is calculated as 16T/ld², making the correct answer B. 16T/ld².

Step-by-step explanation:

The student's question pertains to the average shear stress that develops in a square key used to transmit torque between a shaft and a pulley.

To calculate this shear stress, a few mechanical concepts come into play such as torque, shear force, and cross-sectional area.

Shear stress (usually denoted as τ) is defined as the shear force F applied perpendicular to the cross-sectional area A, which for a square key with side d/4 would be

(d/4) × (d/4) = d²/16.

Since the torque T is transmitted by the key, the shear force F is equal to the torque T divided by the radial distance from the center, which in this case would be d/2.

Therefore, the average shear stress τ is given by the formula:

τ = F/A = (4T/d)/(d²/16) = 16T/ld²

Hence, the correct answer to the question is B. 16T/ld².

User Ahmad Hindash
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