Final answer:
The solubility of argon gas in water can be calculated using Henry's law equation. Given the partial pressure of argon gas and the Henry's law constant, the solubility can be determined as 240 kbar.bar.
Step-by-step explanation:
According to Henry's law, the solubility of a gas in a liquid is directly proportional to the pressure of the gas above the liquid. The Henry's law equation is given by Cg = k * Pg, where Cg is the solubility of the gas, k is the Henry's law constant, and Pg is the partial pressure of the gas. To calculate the solubility of argon gas in water, we can use the equation Cg = k * Pg and plug in the given values.
Given:
- Partial pressure of argon gas (Pg) = 6 bar
- Henry's law constant for argon dissolved in water (k) = 40 kbar
Substituting these values into the Henry's law equation, we have:
Cg = 40 kbar * 6 bar = 240 kbar.bar
Therefore, the solubility of argon gas in water is 240 kbar.bar.