Question

a bag contains 5 black and 6 red balls. determine the number of ways in which 2 black and 3 red balls can be selected.

Answer 1

The number of ways to select 2 black and 3 red balls from the bag is 200.

Step-by-step explanation:

To determine the number of ways to select 2 black and 3 red balls from a bag containing 5 black and 6 red balls, we can use combination formula. The formula for combination is given by nCr = n! / (r! * (n-r)!), where n is the total number of items and r is the number of items to be selected.

In this case, we have 5 black balls and we want to select 2 of them, so n = 5 and r = 2. Similarly, we have 6 red balls and we want to select 3 of them, so n = 6 and r = 3. Plugging these values into the formula, we get:

Number of ways to select 2 black balls from 5 black balls = 5C2 = 5! / (2! * (5-2)!) = 10

Number of ways to select 3 red balls from 6 red balls = 6C3 = 6! / (3! * (6-3)!) = 20

Therefore, the number of ways to select 2 black and 3 red balls from the bag is:

Number of ways = 10 * 20 = 200.