137k views
0 votes
A gas mixture was passed at the rate of 2.50 L/min through a solution of sodium hydroxide for a total of 59.00 min. The SO₂ in the mixture was retained as sulfite ion:

SO₂( g) + 2OH¯ --> SO₃²- + H₂O
After acidification with HCl, the sulfite was titrated with 5.15 mL of 0.002997 M KIO₃:
IO₃¯ + 2H₂SO₃ + 2Cl¯ ---> ICl²¯ + 2SO₄⁴ + 2H+ + H₂O
Use 1.20 g/L for the density of the mixture and calculate the concentration of SO₂ in ppm.

1 Answer

3 votes

Final answer:

To calculate the concentration of SO₂ in ppm, we need to determine the moles of SO₂ and the total volume of the gas mixture. First, calculate the moles of SO₂ using the ideal gas law. Then, find the partial pressure of SO₂ using Dalton's Law of Partial Pressures. Finally, convert the moles of SO₂ to ppm by dividing by the total volume of the gas mixture.

Step-by-step explanation:

To calculate the concentration of SO₂ in ppm, we need to determine the moles of SO₂ and the total volume of the gas mixture. First, we can find the moles of SO₂ using the ideal gas law:

moles of SO₂ = (pressure of SO₂) * (volume of SO₂) / (gas constant * temperature)

The pressure of SO₂ can be found using Dalton's Law of Partial Pressures:

partial pressure of SO₂ = (total pressure of gas mixture) * (mole fraction of SO₂)

Finally, we can convert the moles of SO₂ to ppm by dividing by the total volume of the gas mixture:

concentration of SO₂ in ppm = (moles of SO₂ / total volume of gas mixture) * 1,000,000

User Funseiki
by
7.5k points