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Using the equation, complete the table 0 4 -2 6. vertex

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The completed table obtained by calculating the value of y for a specified value of x can be presented as follows;


\begin{tabular} c \cline{1-2}x & y \\ \cline{1-2}1 & -3 \\\cline{1-2}3 &-3 \\\cline{1-2}0 & 6 \\\cline{1-2}4&6\\\cline{1-2}\end{tabular}

The table can be completed by calculating the y-values for the specified x-values as follows;

The equation is; y = 3·x² - 12·x + 6

Therefore, when x = 1, we get;

y = 3 × 1² - 12 × 1 + 6

3 × 1² - 12 × 1 + 6 = -3

y = -3

Where x = 3, we get;

y = 3 × 3² - 12 × 3 + 6

3 × 3² - 12 × 3 + 6 = -3

y = -3

Where x = 0, we get;

y = 3 × 0² - 12 × 0 + 6

3 × 0² - 12 × 0 + 6 = 6

y = 6

Where x = 4, we get;

y = 3 × 4² - 12 × 4 + 6

3 × 4² - 12 × 4 + 6 = 6

y = 6

The completed table is therefore;


\begin{tabular} \cline{1-2}x & y \\ \cline{1-2}1 & -3 \\\cline{1-2}3 &-3 \\\cline{1-2}0 & 6 \\\cline{1-2}4&6\\\cline{1-2}\end{tabular}

The complete question obtained from a similar question found through search can be presented as follows;

y = 3·x² - 12·x + 6

Vertex (2, -6)

User Alessandro Cuttin
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