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A block with a mass of 5 kg is pushed on a frictionless surface through a distance of 5 m by applying a horizontal force of 80 N. If the block starts from rest, what is its final velocity?

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Final answer:

The final velocity of the block is approximately 12.65 m/s.

Step-by-step explanation:

To find the final velocity of a block, we can use the equation:

v^2 = u^2 + 2as

Where:

  • v is the final velocity
  • u is the initial velocity, which is 0 m/s since the block starts from rest
  • a is the acceleration, which can be calculated using Newton's second law (F = ma)
  • s is the distance traveled, which is 5 m

First, we need to find the acceleration:

F = ma

80 N = 5 kg * a

a = 16 m/s^2

Now, we can calculate the final velocity:

v^2 = 0^2 + 2(16)(5)

v^2 = 160

v = √160

v ≈ 12.65 m/s

Therefore, the final velocity of the block is approximately 12.65 m/s.

User Fredericrous
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