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A d-block element forms an octahedral complex but its spin magnetic moment remains the same in the presence of both strong field and weak field ligands. Which of the following is/are correct?

A. It always forms colourless compounds
B. The number of electrons in t₂ orbitals is more than those in e orbitals
C. It can have either d³ or d⁸ configuration
D. It can have either d⁷ or d⁸ configuration

1 Answer

4 votes

Final answer:

The d-block element with an unchanged spin magnetic moment in different ligand fields can have a d³ or d¸ electronic configuration, making option C the correct answer.

Step-by-step explanation:

A d-block element with a consistent spin magnetic moment in the presence of both strong field and weak field ligands suggests that the electronic configuration is not influenced by the ligand field. For instance, a d³ or d¸ configuration would demonstrate this effect because the number of unpaired electrons does not change with different ligand fields. The possible configurations could be:

  • d³: All three electrons are unpaired and will remain unpaired, regardless of the ligand field strength.
  • d¸: Two unpaired electrons exist, and low-spin or high-spin distinctions do not apply, since both t₂₂g and e₂g orbitals will be partially filled.

Let's evaluate the proposed options:

  • A. This is incorrect because the presence of unpaired electrons typically results in colored compounds.
  • B. This is also incorrect as there's no explicit information about the relative filling of t₂g and e₂g orbitals in the question.
  • C. This option is correct because either a d³ or d¸ configuration can show unchanged spin magnetic moments in different ligand fields.
  • D. This is incorrect because a d· configuration would show a difference in the number of unpaired electrons when subjected to strong versus weak field ligands, which would change the magnetic properties.

Therefore, the correct option in the final answer is C: it can have either d³ or d¸ configuration.

User Seth Kitchen
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