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A spherical rubber balloon carries a charge that is uniformly distributed over its surface. as the balloon is blown up and increase its size how does the total electric flux coming out of the surface change?

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Final answer:

The total electric flux from a charged spherical balloon remains constant regardless of its size because the increase in surface area is counteracted by the decrease in electric field intensity, in accordance with Gauss's Law.

Step-by-step explanation:

When a spherical rubber balloon, carrying a total charge Q uniformly distributed over its surface, is blown up to increase its size, the total electric flux emanating from its surface remains constant. This is a direct consequence of Gauss's Law, which states that the electric flux through a closed surface is proportional to the enclosed charge irrespective of the surface size.

As the radius of a charged balloon changes, say from R to 2R, the surface area increases by a factor of four (since the area of a sphere is 4πr²), but the electric field strength at any point on the surface decreases by a factor of the square of the radius due to the inverse-square law. These changes counterbalance each other, resulting in an unchanged total electric flux. Therefore, when inflating the balloon from radius R to 2R, the electric flux through the surface does not change over time.

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