Final answer:
The assertion that a lower power bulb emits more light than a higher power bulb in a series circuit is false, as is the reason given that the lower power bulb receives more current. The higher power bulb will emit more light due to its lower resistance, given that the current is constant in a series circuit.
Step-by-step explanation:
The assertion that in a series combination of electric bulbs, the bulb of lower power emits more light than that of the highest power is false. In a series circuit, all components have the same current passing through them. The power dissipated by a bulb is given by the formula P = I^2R, where I is the current and R is the resistance. The bulb with lower power has a higher resistance. Since the current is the same through all bulbs in series, the bulb with higher resistance (lower power) will not emit more light but will instead dissipate less power than the bulb with lower resistance (higher power). Therefore, the higher power bulb will emit more light.
The reason provided that the lower power bulb in series gets more current than the highest power bulb is also false. As stated before, the current remains constant through each component in a series circuit, regardless of the power rating of the bulbs.
In conclusion, the correct answer to the initial question is D: Statement I is false but Statement II is true.