Final answer:
To calculate the superelevation and speed on the branch line, use the concept of centrifugal force and the equation for maximum speed on a curved track.
Step-by-step explanation:
The superelevation on the branch line will be 5°. The maximum speed on the branch line can be calculated using the equation v = √(R × 9.8 × tan(8°)).
To calculate the superelevation and speed on the branch line, we need to use the concept of centrifugal force and the equation for maximum speed on a curved track.
The superelevation is the angle at which the outer rail of a curved track is raised above the inner rail to counteract the centrifugal force. In this case, the main curve has a 5° angle, so the superelevation on the branch line will also be 5°.
The maximum speed on a curved track can be calculated using the equation:
v = √(R × g × tan(θ))
Where v is the speed, R is the radius of the curve, g is the acceleration due to gravity (9.8 m/s²), and θ is the angle of the curve.
Given that the maximum speed permitted on the main line is 45 km/h, we can use this equation to calculate the maximum speed on the branch line:
v = √(R × 9.8 × tan(8°))
Using this equation, we can find the radius of the curve on the branch line and then calculate the maximum speed.