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In a case presented in front of judge, lawyer a speaks truth for 60% cases and lawyer b speaks truth for 75% of cases. in what percentage of cases are they likely to contradict each other while narrating the same incident.

A. 85%
B. 85%
C. 45%
D. 67.50%

1 Answer

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Final answer:

Lawyer A and B will likely contradict each other in 45% of cases when narrating the same incident. This is found by adding the probabilities of one telling the truth while the other lies for both scenarios.

The answer is C. 45%.

Step-by-step explanation:

To calculate the percentage of cases in which lawyers A and B are likely to contradict each other while narrating the same incident, we need to consider when one tells the truth while the other lies. Lawyer A speaks the truth in 60% of cases, which means they lie in 40% of the cases. Lawyer B speaks the truth in 75% of cases, which implies they lie in 25% of the cases. The scenarios where they contradict each other are when A speaks the truth and B lies (60% * 25%) or when A lies and B speaks the truth (40% * 75%).

The percentage of cases where they contradict each other is calculated as follows:

  • Probability(A truth and B lie) = 60% × 25% = 15%
  • Probability(A lie and B truth) = 40% × 75% = 30%

Adding these two probabilities gives us the overall percentage of contradiction:

Probability of contradiction = Probability(A truth and B lie) + Probability(A lie and B truth)

Probability of contradiction = 15% + 30% = 45%

The answer is C. 45%.

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