Question

Given a binary string consisting of only Os and 1s, write an algorithm to find the number of different ways to get the longest consecutive sub-segment of is only. You are allowed to change any K number of Os to 1s. If two ways lead to the same string, they are considered to be similar, nor different. Input The first line of the input consists of the string(5) The second line consists of an integer changek representing the number of changes you can make (19. N Output Print an integer representing the number of different ways possible to get the longest consecutive sub-segment of 15. Constraints 13 size of strings 210 o changes site Example lopun 101010 Constraints 15 size of string 2 109 Os changeks size Example Input: 1010101 1 Output: 3 Explanation: Since only one change is allowed the different combinations possible are 1110101 1011101 and 1010111. In all the possible combinations the maximum reading with consecutive is is 1011101 Le 111 so 3 is the output. 1-import java.util. 2 import java.lang.; 3 import java.io.*; 4 5/ 6 strs is the given string 7 changek is the number of changes you can make. 8 9 public class Solution 10- 11 public static int longSubseg(String stes, int changer) 12 13 int answer = 0; 7 Write your code here 15 1 12 return answer 18 1 punite static id main(String[] args) Scanner in = new Scanner(System.in). 20 21 22 23 24 25 26 27 28 29 String strs = in.nextLine); input for change int change in.nextInt : 31 32 Iht result = TongSubsesstes, change); Systes out interesit); 35

Answer 1

To solve this problem, iterate over the binary string, keeping track of the longest consecutive subsegment of 1s, and making changes to 0s if available. Finally, return the maximum length of the consecutive subsegment of 1s.

Step-by-step explanation:

To solve this problem, we can iterate over the binary string and keep track of the longest consecutive subsegment of 1s. Whenever we encounter a 0, we try to change it to 1 if we have remaining changes available. This way, we maximize the length of the consecutive subsegment of 1s.

Here is the algorithm:

1. Initialize variables: maxLength = 0, currentLength = 0, remainingChanges = changek.
2. Iterate over the binary string:
3. If the current bit is 1, increment currentLength.
4. If the current bit is 0:
5. If remainingChanges is greater than 0, increment currentLength and decrement remainingChanges.
6. If remainingChanges is 0, update maxLength with max(maxLength, currentLength) and reset currentLength to 0.
7. Update maxLength with max(maxLength, currentLength).
8. Return maxLength.

In the given example '1010101' with changek = 1, the algorithm will output 3, because the maximum consecutive subsegment of 1s can be achieved with the following combinations: '1110101', '1011101', and '1010111'.