Final answer:
To find the instantaneous value of the current at a specific time after reaching the maximum positive value, the sinusoidal function I(t) = I0sin(ωt) is used, taking into account the frequency, angular frequency, and RMS value provided.
Step-by-step explanation:
To find the instantaneous value of an alternating current 0.0025 seconds after it passes through the maximum positive value, we will use the sinusoidal function of AC voltage and current. Given that the frequency is 50 Hz, we can calculate the angular frequency (ω) as ω = 2πf = 2π(50) radians/second. The root mean square (RMS) value of the current is given as 40 A, so the peak current (I0) can be found using I0 = Irms√2 = 40A√2. The sinusoidal function for the current is I(t) = I0sin(ωt).
To find the instantaneous current at t = 0.0025 seconds, we substitute the values: I(0.0025) = I0sin(2π(50)(0.0025)) = 40A√2sin(π/8). Hence, the instantaneous value can be calculated using this equation.
To find the instantaneous value of an alternating current 0.0025 seconds after passing through its maximum positive value, we need to consider the frequency and rms value of the current.
Given that the current varies sinusoidally with a frequency of 50 Hz and has an rms value of 40 A, we can use the equation: I = I0sin(ωt), where I is the instantaneous value, I0 is the maximum positive value, ω is the angular frequency (2πf), and t is the time in seconds.
Plugging in the values, we have: I(0.0025s) = 40A * sin(2π(50)(0.0025)).
Calculating that, we find the instantaneous value of the current 0.0025 seconds after passing through its maximum positive value.