Final answer:
The magnitude of the two like parallel forces acting at a distance of 24 mm apart, with a resultant force of 20 N located 6 mm from one of the forces, is 5 N each. As none of the given options match this result, the answer is D. none of these.
Step-by-step explanation:
The question relates to the topic of parallel forces in physics, particularly involving their resultant and distances. Given that the resultant force is 20 N and it acts at a distance of 6 mm from one of the equal forces, we can use the principle of moments to solve for the individual forces. According to this principle, the moment of the resultant force about any point is equal to the algebraic sum of the moments of the component forces about the same point.
To find the magnitude of the two like parallel forces, we can denote one force as F and the other as F (since they are stated to be like and equal). The perpendicular distance between the forces is 24 mm. If we take moments about the point where one force acts, we can set up the following equation (moment = force x distance):
20 N (6 mm) = F (24 mm)
120 N·mm = 24F N·mm
To solve for F, we divide both sides by 24 mm:
F = 120 N·mm / 24 mm = 5 N
Since the two forces are equal, the forces are 5 N and 5 N, which does not match any of the given options, so the correct answer is D. none of these.