Question

a projectile is fired from horizontal ground with speed and projection angle . when the acceleration due to gravity is , the range of the projectile is . if at the highest point in its trajectory, the projectile enters a different region where the effective acceleration due to gravity is g' = 9/0.81 then the new range is d' = nd . The value of n is _______.

Answer 1

The range of a projectile on level ground depends on the initial speed, projection angle, and acceleration due to gravity. When the acceleration due to gravity changes, the new range can be calculated using a factor called n. In this case, n = 11.11.

Step-by-step explanation:

The range of a projectile depends on its initial velocity and projection angle as well as the acceleration due to gravity. In this case, the range of the projectile on level ground is given by the equation:

R = (vo^2 * sin(2*theta)) / g

Where vo is the initial speed, theta is the projection angle, and g is the acceleration due to gravity.

When the projectile enters a region with a different acceleration due to gravity, the new range can be calculated using the equation:

R' = n * d

Where R' is the new range, d is the range on level ground, and n is the factor by which the range is increased or decreased due to the change in acceleration. In this case, n = g / g' = 9 / 0.81 = 11.11.