77.5k views
3 votes
A rod is thrown with speed u at an angle theta with angular velocity omega. Find the coordinate at time t.

A. ut - (1/2)gt²
B. ut + (1/2)gt²
C. ucos(θ)t
D. usin(θ)t

1 Answer

5 votes

Final answer:

The coordinate of the rod at time t can be found using the equations of projectile motion. The horizontal component of the motion is given by x = utcos(θ)t and the vertical component is given by y = utsin(θ)t - (1/2)gt^2. The correct answer choice is D. usin(θ)t.

Step-by-step explanation:

The coordinate of the rod at time t can be found using the equations of projectile motion. We can separate the motion of the rod into horizontal and vertical components. The horizontal component of the motion is given by x = utcos(θ)t, where x is the horizontal distance traveled. The vertical component of the motion is given by y = utsin(θ)t - (1/2)gt^2, where y is the vertical distance traveled and g is the acceleration due to gravity.

Since we are only concerned with the coordinate at time t, we can ignore the angular velocity omega. Therefore, the correct answer choice is D. usin(θ)t.

User Brebs
by
8.5k points