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If the length of the pendulum in a pendulum clock increases by 0.1%, then the error in time per day is:

A. 43.2 s
B. 4.32 s
C. 0.432 s
D. 0.0432 s

1 Answer

2 votes

Final answer:

The error in time per day for a pendulum clock due to a 0.1% increase in its length involves calculating the proportional change in the period and converting it to seconds over a day. An exact answer cannot be provided without the steps to solve for this specific percentage change.

Step-by-step explanation:

The question is about determining the error in time per day for a pendulum clock if the length of the pendulum is increased by 0.1%. This is a classic physics problem that involves the concept that the period of a simple pendulum is proportional to the square root of its length. Since the period is directly related to the timekeeping of the clock, any change in length will affect the time the clock keeps.

The calculation involves using the formula for the period of a pendulum (T = 2π√(L/g)) and understanding that if the length L increases by a certain percentage, the period T will also change accordingly, affecting the time kept by the clock over one day.

However, without the exact formula or the required steps to solve the specific error in time per day due to a 0.1% increase in pendulum length, we can't provide a precise answer. Still, normally, the process would involve making an approximate calculation using the proportional change in the period resulting from the change in length and then converting the change in period to seconds over the course of a day (86,400 seconds).

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