Question

The hydrated salt Na₂CO₃​⋅xH₂​O undergoes a 63% loss in mass on heating, and becomes Na₂​CO₃​. The value of x is___

Answer 1

To find the value of x, we calculate the percent loss in mass and use it to find the number of moles of water in the hydrated salt Na2CO3⋅xH2O. The value of x is 2.917 g.

Step-by-step explanation:

To determine the value of x, we need to calculate the percent loss in mass and use it to find the number of moles of water in the hydrated salt Na₂CO₃⋅xH₂O. We are given that the mass of the hydrated salt is 4.640 g and the mass of the anhydrous Na₂CO₃ is 1.720 g. The percent loss in mass can be calculated using the formula:

Percent loss in mass = (Mass of water lost / Initial mass of hydrated salt) * 100%

Substituting in the given values, we have:

63% = (x / 4.640) * 100%

Solving for x:

x = (63% * 4.640) / 100% = 2.917 g

Therefore, the value of x is 2.917.