177k views
0 votes
A manufacturer produces two types of steel trunks. He has two machines a and b. The first type of trunk requires 3 hours on machine a and 3 hours on machine b. The second type of trunk requires 3 hours on machine a and 2 hours on machine b. machine a and b can work almost for 18 hours and 15 hours per day respectively. How many trunk of each type must he make each day to make maximum profit?

User Tofuw
by
9.4k points

1 Answer

7 votes

Final answer:

To determine the number of trunks of each type the manufacturer must make each day to maximize profit, we need to set up a system of linear equations and use linear programming to find the optimal solution.

Step-by-step explanation:

To determine the number of trunks of each type the manufacturer must make each day to maximize profit, we can set up a system of linear equations. Let's assume that x represents the number of trunks of the first type, and y represents the number of trunks of the second type.

The time required on machine a can be modeled by the equation 3x + 3y, and the time required on machine b can be modeled by the equation 3x + 2y. We also know that the machine a can work for 18 hours and machine b can work for 15 hours per day.

Therefore, the constraints for the machines are 3x + 3y ≤ 18 and 3x + 2y ≤ 15. Finally, the objective is to maximize profit, which is given by the function P = 200x + 200y.

In order to find the optimal solution, we can use a technique called linear programming. By graphing the feasible region and evaluating the profit at each corner point, we can identify the combination of trunk production that yields the maximum profit.

This can be done using a graphing calculator or by solving the system of equations and evaluating the profit at each solution. The solution that maximizes profit would be the one that yields the highest value for P.

User Ramalingam Perumal
by
7.5k points