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A projectile has an initial speed of 3.58 m/s when fired horizontally. When fired at an angle of 36° from the horizontal, what would be the vertical component of its velocity the moment it leaves the mechanism?

o 0 m/s
o 2.10 m/s
o 2.90 m/s
o 3.58 m/s

1 Answer

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Final answer:

The vertical component of velocity for a projectile fired at an angle can be calculated using the initial speed and the sine of the launch angle. For an initial speed of 3.58 m/s and an angle of 36°, this is done by multiplying the initial speed with the sine of the angle.

Step-by-step explanation:

When calculating the vertical component of the velocity for a projectile launched at an angle, we use the initial speed and the sine of the launch angle. Given an initial speed of 3.58 m/s and a launch angle of 36° from the horizontal, the vertical component of the velocity (Vy) can be calculated using the equation:

Vy = V × sin(θ)

Where V is the initial speed and θ is the angle of launch. Plugging in the values, we get:

Vy = 3.58 m/s × sin(36°)

You would need a calculator to find the sine of 36° and then multiply it by 3.58 m/s to get the vertical component of the velocity. This component of velocity determines the vertical motion of the projectile and is crucial for calculating how long the projectile will stay in the air and the maximum height it will reach.

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