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Write an equation for a parabola with​ x-intercepts (-1,0) and (5,0) which pass through the point (4,-25)

User Maziyar
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Final answer:

The equation for a parabola with x-intercepts (-1,0) and (5,0) that passes through the point (4,-25) is y = 5(x + 1)(x - 5).

Step-by-step explanation:

To write an equation for a parabola with x-intercepts (-1,0) and (5,0) which passes through the point (4,-25), we can start with the form y = a(x - r)(x - s), where r and s are the x-intercepts of the parabola.

Given the x-intercepts (-1,0) and (5,0), our equation becomes:

y = a(x + 1)(x - 5)

To find the value of a, we will substitute the coordinates of the point (4, -25) into the equation and solve for a:

-25 = a(4 + 1)(4 - 5)

By simplifying and solving, we get:

-25 = a(5)(-1)

a = 5

So, the equation of the parabola is:

y = 5(x + 1)(x - 5)

User Robert Monfera
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