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1 vote
Draw the Lewis structure for C₂H4. How many o and how many n bonds are

present?
50 and 1n
4o and 2n
30 and 2 n
5 σ and 2 n

1 Answer

5 votes

The Lewis structure for C₂H₄ is:

H

|

C

|

H

In the Lewis structure of C₂H₄, there is a double bond between the carbon atoms.

  • Each single bond (sigma bond) contributes one sigma (σ) bond.
  • Each double bond contains one sigma (σ) bond and one pi (π) bond.

Therefore, the number of sigma (σ) bonds is 5, and the number of pi (π) bonds is 1.

The Lewis structure for C₂H₄ (ethylene) shows a double bond between two carbon atoms, each bonded to two hydrogen atoms. This arrangement satisfies the octet rule for carbon and the duet rule for hydrogen.

The molecule contains 5 sigma (σ) bonds, representing single bonds and the sigma bond in the double bond. Additionally, there is 1 pi (π) bond within the double bond.

User Sourav Gulati
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