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Solve the following equation

K+3/7-2(k-4)/4 =1

1 Answer

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Final answer:

To solve the equation K+3/7-2(k-4)/4 = 1, distribute the negative sign, combine like terms, convert fractions to have a common denominator, simplify the fraction, get rid of the fraction, combine like terms, subtract 17 from both sides of the equation, and divide both sides by -7 to find that k = 10/7.

Step-by-step explanation:

To solve the equation K+3/7-2(k-4)/4 =1:

1. Distribute the negative sign to the terms inside the parentheses: K + 3/7 - 2k + 8/4 = 1

2. Combine like terms: K - 2k + 3/7 + 8/4 = 1

3. Convert the fractions to have a common denominator: K - 2k + 12/28 + 56/28 = 1

4. Combine the fractions: K - 2k + 68/28 = 1

5. Simplify the fraction and convert it to a mixed number: K - 2k + 17/7 = 1

6. Get rid of the fraction by multiplying both sides of the equation by 7: 7K - 14k + 17 = 7

7. Combine like terms: -7k + 17 = 7 - 7K

8. Subtract 17 from both sides of the equation: -7k = -10

9. Divide both sides of the equation by -7: k = 10/7

User Gustavo Cardoso
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