Answer:
To solve the quadratic equation x^2 - 8x + 7 = 0, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this equation, a, b, and c represent the coefficients of the quadratic equation.
For the given equation x^2 - 8x + 7 = 0, we have:
a = 1, b = -8, c = 7
Plugging these values into the quadratic formula:
x = (-(-8) ± √((-8)^2 - 4(1)(7))) / (2(1))
Simplifying the equation further:
x = (8 ± √(64 - 28)) / 2
x = (8 ± √36) / 2
x = (8 ± 6) / 2
This gives us two possible solutions:
1. When x = (8 + 6) / 2:
x = 14 / 2
x = 7
2. When x = (8 - 6) / 2:
x = 2 / 2
x = 1
Therefore, the solutions to the equation x^2 - 8x + 7 = 0 are x = 7 and x = 1.
Explanation: