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Find the cosine of ZQ. 48 P 73 55 R Simplify your answer and write it as a proper fraction, improper fraction, or whole number. cos (Q): =​

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the cosine of ZQ is 2/3 as an improper fraction or 0.6666... as a decimal.

Identify the relevant sides and angle:

Adjacent side to ZQ: PQ = 48

Hypotenuse of triangle PQR: PR = 73

Use the cosine function:

Cosine (ZQ) = Adjacent side / Hypotenuse

Cos (ZQ) = PQ / PR

Cos (ZQ) = 48 / 73

Simplify the answer:

Cos (ZQ) = 16/24 = 2/3 (improper fraction)

Cos (ZQ) can also be written as 0.6666... (decimal)

Therefore, the cosine of ZQ is 2/3 as an improper fraction or 0.6666... as a decimal.

User Dominic Sayers
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