Answer:
BD = AC (given)
BD || AC (given)
W is the midpoint of AB (given)
Q is the midpoint of BC (given)
AW = WB (definition of midpoint)
BQ = QC (definition of midpoint)
Angle BCA = Angle DBC (alternate interior angles are congruent)
∆BCA = ∆DBC (SAS)
Angle ABC = Angle DCB (CPCTC)
∆ABC = ∆DCB (SAS)