Question

You are facing a loop of wire which carries a clockwise current of

3.0 A and which surrounds an area of 5.8 × 10−2 m2 . The magnetic
dipole moment of the loop is:

Answer 1

The magnetic dipole moment of the loop is 0.174 A·m^2.

Step-by-step explanation:

The magnetic dipole moment (µ) of a current-carrying loop is calculated by multiplying the current (I) with the area (A) of the loop. In this case, the current is 3.0 A and the area is 5.8 × 10-2 m2. So, the magnetic dipole moment of the loop is:

µ = I × A

µ = (3.0 A)(5.8 × 10-2 m2)

µ = 0.174 A·m2