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Have a sample of 63 with a sample proportion of 57.14% what is the error of confidence interval

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Rounded to three decimal places, the margin of error for a 95% confidence interval based on the given sample proportion and size is approximately 0.122.

To determine the margin of error for a confidence interval based on a sample proportion, you'd typically use the form

Margin of Error=Z× √p(1−p)/n

Where:

Z is the Z-score corresponding to the desired level of confidence.

p is the sample proportion.

n is the sample size.

The Z-score is determined based on the desired confidence level. For example, if you're aiming for a 95% confidence level, the Z-score would be approximately 1.96.

Given:

Sample proportion,

p=57.14%=0.5714

Sample size,

n=63

Assuming a 95% confidence level, the Z-score is approximately 1.96.

Now, plug in these values into the formula:

Margin of Error=1.96× √0.5714×(1−0.5714)/63

Let's calculate:

Margin of Error≈1.96×√0.5714×0.4286/ 63

Margin of Error≈1.96×√ 0.24487724/63

Margin of Error≈1.96× √0.003889476

Margin of Error≈1.96×0.062385627

Margin of Error≈0.122101076

Rounded to three decimal places, the margin of error for a 95% confidence interval based on the given sample proportion and size is approximately 0.122.

User Rexxar
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