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What is the magnitude of the resultant velocity for a bird flying first at a speed of 10 m/s North

East and then flying to South at a speed of 8 m/s?

User Necole
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1 Answer

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Final answer:

The magnitude of the resultant velocity for the bird flying first at a speed of 10 m/s North East and then flying to the South at a speed of 8 m/s is approximately 16.24 m/s.

Step-by-step explanation:

To find the magnitude of the resultant velocity, we can use vector addition.

The bird flies first at a speed of 10 m/s North East and then flies to the South at a speed of 8 m/s.

These velocities can be represented as vectors.

Since the bird is flying at a speed of 10 m/s North East, the vector representing this velocity can be split into its North and East components.

The North component can be found using trigonometry: sin(45°) * 10 = 7.07 m/s.

The East component can be found using trigonometry: cos(45°) * 10 = 7.07 m/s.

The bird then flies at a speed of 8 m/s to the South.

When an object is moving in the opposite direction, we can consider it as having a negative velocity.

So, the South velocity can be represented as -8 m/s.

To find the resultant velocity, we can add the North and East components to the South velocity.

The North component is 7.07 m/s, the East component is 7.07 m/s, and the South velocity is -8 m/s.

Adding these vectors together, we get:

Resultant velocity = 7.07 m/s North + 7.07 m/s East + (-8 m/s South)

= 7.07 m/s North + 7.07 m/s East - 8 m/s South.

Therefore, the magnitude of the resultant velocity is the square root of the sum of the squares of the North, East, and South velocities:

Magnitude of resultant velocity = sqrt((7.07)^2 + (7.07)^2 + (-8)^2)

= sqrt(99.99 + 99.99 + 64)

= sqrt(263.98)

≈ 16.24 m/s.

User Dotz
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