Question

An open vessel containing oil with specific gravity of 0.70 moves in a vertical direction with an acceleration of 8 m/s2. Calculate the intensity of pressure (in kPa) at a point 3 m below the liquid surface when it moves upward. Round off you answer to one decimal place.

Answer 1

The intensity of pressure at a point 3 m below the liquid surface when it moves upward is 20.6 kPa.

Step-by-step explanation:

To calculate the intensity of pressure at a point 3 m below the liquid surface, we can use the equation:

Pressure = pressure due to column of oil + pressure due to acceleration

To calculate the pressure due to the column of oil, we can use the formula:

Pressure = density × gravity × height

Given that the specific gravity of the oil is 0.70, we can say that the density of the oil is 0.70 times the density of water (1000 kg/m3).

Therefore, the density of the oil is 700 kg/m3.

Using the given acceleration of 8 m/s2 and the height of 3 m, we can calculate the pressure due to acceleration.

By substituting the values into the equation, we get:

Pressure = (700 kg/m3) × (9.8 m/s2) × 3 m

Pressure = 20,580 Pa

Since 1 kPa = 1000 Pa, the pressure is:

Pressure = 20,580 Pa / 1000

= 20.6 kPa