Final answer:
To determine the volume of the 0.275 M KMnO4 solution required to completely react with 3.30 g of Zn, we can use the balanced equation and molarity of KMnO4 to calculate the number of moles of KMnO4 needed and then convert to volume using the molarity. The volume of a 0.275 M KMnO4 solution is 0.149 L or 149 mL.
Step-by-step explanation:
To determine the volume of the 0.275 M KMnO4 solution required to completely react with 3.30 g of Zn, we first need to write a balanced equation for the reaction:
2 KMnO4 + 3 Zn → 2 MnO2 + 2 K2O + 3 ZnO
From the balanced equation, we can see that 2 moles of KMnO4 are required to react with 3 moles of Zn. We can use this ratio to calculate the number of moles of KMnO4 needed:
moles of KMnO4 = (3.30 g Zn) / (65.38 g/mol Zn) × (2 mol KMnO4 / 3 mol Zn)
= 0.0410 mol KMnO4
Finally, to calculate the volume of the solution, we can use the molarity of KMnO4:
volume of solution = moles of KMnO4 / molarity of KMnO4
= 0.0410 mol / 0.275 M
= 0.149 L or 149 mL