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a uniform magnetic field b with magnitude 1.2 mt is directed vertically upwards throught the volume of a lab chamber. a proton with ke 5.3 mev enters the chamber moving horizontally from shouth to north. what magnetic deflecting force acts on the proton as it enters the chamber

User Swietyy
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Final answer:

The magnetic deflecting force on a proton can be computed using the formula F = qvB, considering the charge of the proton and its velocity, which is derived from its kinetic energy. The result provides the magnetic force experienced by the proton as it traverses a vertical magnetic field.

Step-by-step explanation:

To calculate the magnetic deflecting force acting on a proton as it enters a lab chamber with a vertical magnetic field, we use the formula for magnetic force, F = q(v x B), where q is the charge of the proton, v is the velocity, and B is the magnetic field. Assuming the velocity vector is perpendicular to the magnetic field, the force becomes F = qvB, with the direction given by the right-hand rule.

TT

A proton has a charge of approximately 1.6 x 10^-19 coulombs (C). Given the kinetic energy (KE) is 5.3 MeV, which is 5.3 x 10^6 eV, we can find the velocity using the relation KE = (1/2)mv^2. After converting the kinetic energy from electron volts to joules (1 eV = 1.6 x 10^-19 J), and solving for v, we can use the resultant speed within the magnetic force equation to calculate the force acting on the proton.

The given magnetic field strength B is 1.2 mT or 1.2 x 10^-3 T when converted to tesla. Substituting the knowns into the equation calculates the magnetic force acting on the proton as it enters the lab chamber.

User Florim Maxhuni
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