Question

How many milliliters of 5.0 M copper(II) sulfate solution must be added to 160 ml of water to achieve a 0.30 M copper(II) sulfate solution?

A) 240 ml
B) 300 ml
C) 480 ml
D) 600 ml

Answer 1

To achieve a 0.30 M copper(II) sulfate solution, you would need to add approximately 9.6 mL of a 5.0 M copper(II) sulfate solution to 160 mL of water.

Step-by-step explanation:

To solve this problem, we can use the dilution equation:

Cₛ₁V₁ = C₂V₂

Where Cₛ₁ is the initial concentration, V₁ is the initial volume, C₂ is the final concentration, and V₂ is the final volume.

We can plug in the values:

(5.0 M)(x mL) = (0.30 M)(160 mL)

Solving for x, we get:

x = (0.30 M)(160 mL) / (5.0 M)

x ≈ 9.6 mL

Therefore, you would need to add approximately 9.6 mL of the 5.0 M copper(II) sulfate solution to 160 mL of water to achieve a 0.30 M copper(II) sulfate solution.

Answer 2

To achieve a 0.30 M copper(II) sulfate solution, you would need to add approximately 267 ml of the 5.0 M copper(II) sulfate solution to 160 ml of water. So, the correct option is A) 240 ml.

Step-by-step explanation:

To calculate the volume of 5.0 M copper(II) sulfate solution needed to achieve a 0.30 M solution, we can use the dilution equation: C₁V₁ = C₂V₂. Rearranging the equation, we have V₂ = (C₁V₁) / C₂. Substitute the given values: C₁ = 5.0 M, V₁ = 0.160 L, and C₂ = 0.30 M. Solving for V₂, we get V₂ ≈ 0.267 L.

To convert from liters to milliliters, we multiply by 1000. Therefore, the volume in milliliters is 0.267 L * 1000 = 267 ml. So, you would need to add approximately 267 ml of the 5.0 M copper(II) sulfate solution to 160 ml of water to achieve a 0.30 M copper(II) sulfate solution. Hence, the correct option is A) 240 ml.