The solution to the system of equations is
Let's solve the system of equations algebraically:
1. Equation 1: y = 4x - 5
2. Equation 2: y = -3
To find the solution, set the right-hand sides of the equations equal to each other:
4x - 5 = -3
Now, solve for x :
4x = -3 + 5
4x = 2
![\[ x = (2)/(4) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/wu7la4x5kt5cpq2znvkhj19xs1ko2mvxjg.png)
![\[ x = (1)/(2) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/5trgbkaz1znnaqvhml4snc33u37hhn43p4.png)
Now that we have
, substitute it back into either equation to find
y. Let's use Equation 1:
![\[ y = 4 * (1)/(2) - 5 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/v9ah105ecv2e4e6750pqpdyh5br066ruto.png)
y = 2 - 5
y = -3
So, the solution to the system is
.
Now, let's verify this solution using the graph:
The point
should satisfy both equations. When you substitute
and y = -3 into the original equations, both should be true. Verify this to confirm the solution.