Question

One reaction step in the conversion of ammonia to nitric acid involves converting NH3 to NO by the following reaction:

4 NH3(g) + 5 O2(g) --> 4 NO(g) + 6 H2O(g)

If 1.50 g of NH3 reacts with 2.75 g O2, then:
1. Which is the limiting reactant?
2. How many grams of NO and H2O form?
3. How many grams of the excess reactant remain after the limiting reactant is completely consumed?

Answer 1

the answer would be 2.75 x 4 nh3