Question

A simple pendulum with mass m = 1.2 kg and length L = 2.46 m hangs from the ceiling. It is pulled back to an small angle of θ = 11° from the vertical and released at t = 0.

What is the period of oscillation?

Answer 1

The period of the simple pendulum with mass 1.2 kg and length 2.46 m that is released from a small angle of 11°, is calculated using the formula T = 2π√(L/g) with the length L and the acceleration due to gravity g.

Step-by-step explanation:

The subject of the question is a simple pendulum, which is a topic typically covered in physics. Given the mass m = 1.2 kg and the length L = 2.46 m of the pendulum, and the fact that it has been released from a small angle (11°), we can calculate the period of oscillation. The formula for the period T of a simple pendulum undergoing simple harmonic motion (SHM) is T = 2π√(L/g), where g is the acceleration due to gravity, approximately equal to 9.81 m/s².

Plugging the values into the formula, we get:

T = 2π√(2.46/9.81)

After calculating, this gives us the period of the pendulum.