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9 votes
9 votes
How far can an object be pushed if 22 J is used with 17.5 N of force? *

A 1.25 meters,
B 0.80 meters
C 4.5 meters
D 385 meters

User Noamt
by
2.5k points

1 Answer

14 votes
14 votes

Answer:


\huge\boxed{\sf d = 1.25\ m}

Explanation:

Given Data:

Work = W = 22 J

Force = F = 17.5 N

Required:

Distance = d = ?

Formula:

W = Fd

Solution:

Put the given data in the above formula.

22 = 17.5 (d)

Divide 17.5 to both sides

22/17.5 = d

1.25 m = d

d = 1.25 m


\rule[225]{225}{2}

User Izak Joubert
by
3.4k points