Question

4x^2+4x^2-20x+12y-2=0 standard form​

Answer 1

y= -2/3x^2 + 5/3x + 1/6

Explanation:

Answer 2

4x²+4y²-20x+12y-2=0

4x²-20x+4y²+12y = 2

4(x²-5x) + 4(y²+3y) = 2

4(x²-5x+25/4) + 4(y²+3y+9/4) = 2 + 4*25/4 + 4*9/4

4(x-5/2)² + 4(y+3/2)² = 36

(x-5/2)² + (y+3/2)² = 9

Explanation:

hope this helped :)