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Evaluate the integral: ∫[eˣ]dx from -[infinity] to [infinity]

A) 0
B) 1
C) e
D) [infinity]

1 Answer

5 votes

Final answer:

The integral evaluates to 0.

Step-by-step explanation:

When evaluating the integral ∫[eˣ]dx from -∞ to ∞, we can break it into three parts: (-∞ to 0), (0 to L), and (L to ∞). However, since the particle is constrained to be in the tube, C = 0 outside the tube, making the first and last integrations zero. Therefore, the integral can be simplified to:

∫[0]dx from 0 to L

Integrating [0]dx is equivalent to integrating the zero function from 0 to L, which results in 0. Therefore, the integral evaluates to 0.

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