Question

The Line Parallel to Line r That Contains (1, -1)

A: Slope-Intercept Form |
B: Point-Slope Form |
C: Parallel Lines Rule |
D: Perpendicular Lines Rule

Answer 1

To find the line parallel to line r that contains the point (1, -1), we can use the point-slope form of a linear equation. The equation of the line parallel to line r that contains the point (1, -1) is y + 1 = 3x - 3.

Step-by-step explanation:

To find the line parallel to line r that contains the point (1, -1), we can use the point-slope form of a linear equation. The point-slope form is given by the equation y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope. Since the line is parallel to line r, it will have the same slope.

We can determine the slope of line r using the given information. The rise is 3 and the run is 1, so the slope is 3/1 = 3. Using the point-slope form and the given point (1, -1), we can substitute the slope and coordinates into the equation to find the line.

So the equation of the line parallel to line r that contains the point (1, -1) is y - (-1) = 3(x - 1), which simplifies to y + 1 = 3x - 3.