Here's the quadratic function in plain text:
a) Standard Form: f(x) = -x^2 + 6x + 16
b) Vertex Form: f(x) = -(x - 3)^2 + 25
c) Factored Form: f(x) = -(x - 2)(x - 8)
d) Intercept Form: f(x) = -1(x - 2)(x - 8)
The quadratic function f(x) = -x^2 + 6x + 16 can be expressed in different forms:
a) Standard Form: f(x) = -x^2 + 6x + 16, which is the given form of the quadratic equation with the terms arranged in standard order.
b) Vertex Form: To express it in vertex form, you'd complete the square, obtaining f(x) = -(x - 3)^2 + 25, revealing the vertex at (3, 25).
c) Factored Form: Factoring the quadratic yields f(x) = -(x - 2)(x - 8), where the roots are 2 and 8.
d) Intercept Form: By factoring and simplifying, the intercept form is f(x) = -1(x - 2)(x - 8), indicating the x-intercepts at 2 and 8.
complete question should be :
Which of the following are different forms of the quadratic function f(x)=−x2+6x+16. a) Standard form
b) Vertex form
c) Factored form
d) Intercept form