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For an electric field given by E=4i−3(y2−2)j, what is the value of Ey​?

A) 3y² - 6
B) 2 - 3y²
C) 3y² + 6
D) 6 - 3y²

1 Answer

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Final answer:

The value of Ey​ in the given electric field equation is -3(y^2 - 2), which simplifies to 3y^2 - 6.

Step-by-step explanation:

To find the value of Ey​, we can use the given electric field equation E=4i−3(y2−2)j. The Ey​ component of the electric field is the coefficient of the j vector. Therefore, Ey​ = -3(y^2 - 2).

So, the correct answer is A) 3y^2 - 6.

User PaulParton
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